Wednesday, February 24, 2016

Control Digital

CONTROL DIGITAL
UNAD 2016

Ejercicio 2a



Respuesta bucla de control ante entradas







===================================================================


Ejercicio 3a



Punto 3a _PID contol Continuo

>> a3= tf([10],[1,2.5,1])

 10
  ---------------
  s^2 + 2.5 s + 1




PID ESTIMATION





Respuesta del controlador PID continuo




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Punto 3b - Controlador PID Discreto


>> a3d = c2d (a3,0.1)

    0.04604 z + 0.04236
  ---------------------
  z^2 - 1.77 z + 0.7788


Sample time: 0.1 seconds







>> a3= tf([10],[1,2.5,1])

      10
  ---------------
  s^2 + 2.5 s + 1

Continuous-time transfer function.

>> a3d = c2d (a3,0.1)

   0.04604 z + 0.04236
  ---------------------
  z^2 - 1.77 z + 0.7788

Sample time: 0.1 seconds
Discrete-time transfer function.





Respuesta del controlador PID Discreto




====================


Punto 3b - PID continuo

>> a4= tf([1],[1,3,2])

    1
  -------------
  s^2 + 3 s + 2

Continuous-time transfer function.








Respuesta en Control Close Loop PID Continuo






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Punto 3b - PID discreto

>> a4d = c2d (a4,0.1)


  0.004528 z + 0.004097
  ----------------------
  z^2 - 1.724 z + 0.7408

Sample time: 0.1 seconds
Discrete-time transfer function.



>> a4= tf([1],[1,3,2])

  1
  -------------
  s^2 + 3 s + 2

Continuous-time transfer function.

>> a4d = c2d (a4,0.1)


  0.004528 z + 0.004097
  ----------------------
  z^2 - 1.724 z + 0.7408

Sample time: 0.1 seconds
Discrete-time transfer function.





Respuesta del control PID discreto